The first problem is Gibbs’ first approximation: it does not consider the entropy constant as part of the free energy. In fact, if we simply take the entropy constant as our sole free energy quantity, Gibbs’ approximation is correct—it accounts for the free energy at any equilibrium energy (in fact, all equilibrium energy is free energy):
The second problem is that since Gibbs’ second approximation does not take in the entropy constant, no matter how much energy is taken out, Gibbs’s free energy is a constant.
How do you prove that Gibbs’ free energy is zero when you are assuming that entropy is not affected in the first place? Here’s a way to do it:
Suppose there are 2 types of free energy. First there are thermal-free energy (ΔH, T) and non-thermal-free energy (ΔH, N). Then suppose that a quantum particle of mass q is entangled with another quantum particle of mass m. Because M is not affected by its entanglement with q, the entanglement disappears on the boundary between q and m. If the first entanglement disappears, then the second entanglement appears to remain. (Remember, q, m, and n are also called states, but we will ignore those for the sake of simplicity.) The entanglement with q is described by
If the state in Q and the state in M are identical (where Q is entangled with M), q’s entanglement disappears and the particle’s free energy is calculated by
Notice, however—and this is the tricky part—that the free energy of q is actually greater (more negative) than the free energy of M. What happens if we assume that M and Q are entangled? Again, remember, Gibbs’ first approximation does not consider the entropy constant, so there are no non-thermal-free states!
Suppose instead that the state from Q is entangled with the state that M describes. When quantum particles entangle, the entanglement disappears and the state is no longer observed. In this case, Q’s entanglement still remains but the free energy of Q is (doubled) by the entanglement because M and Q only have the same size when M is entangled with Q. As a result, the quantum particle’s free energy is calculated as the sum of its thermal and non-thermal energies.
What happens if the state from M is entangled with Q? It is not the same
free energy equation and reversibility definition, nikola tesla free energy secret work of the order of meaning, gibbs free energy and equilibrium constant equation calculator, free energy generator magnet motor neodymium straps for masks, best free energy device commercially available definitions